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A flatbed truck is carrying a 10-kg crate along a level road. The coefficient of static friction between the crate and the bed is 0.5. What is the maximum acceleration in m/s2 that the truck can have if the crate is to stay in place? (2 points)

Added Thu, 06 Aug '15

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The maximum force of static friction will be equal to the coefficient of status friction x the normal force. The normal force is the same is the gravitational force, mg (10kg*9.8). So your normal force is 98Newtons. Multiply by the coefficient (.5) to get 49 Newtons, which is the maximum force of static friction. Force = mass x acceleration. So 49 Newtons = 10kg x acceleration. Divide both sides by 10 to get the mass acceleration by itself.

Added Thu, 06 Aug '15

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