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Mercury is poured into a U-tube. The left arm of the tube has cross-sectional area A1 of 10.4 cm2, and the right arm has a cross-sectional area A2 of 4.90 cm2. One hundred grams of water are then poured into the right arm.

(A) Determine the length of the water column in the right arm of the U-tube. (cm)

(B) Given that the density of mercury is 13.6 g/cm3, what distance h does the mercury rise in the left arm? (cm)
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a) In a U tube, adding 300 grams to one side immediately transfers half of that weight by displacement to the other side. As mercury and water don't mix. the right side will stay pure water above the mercury and the left side will be pure mercury. So we just need to find the volume and then the height for 300 grams of water and 150 grams mercury

150 g/13.6 g/cm^3 = 11 cm^3 mercury
300 g /1 g/cm^3 = 300 cm^3 water

a) ANSWER 300 cm^3 / 4.90 cm^2 = 61.22 cm

b) ANSWER 11 cm^3 / 10.4 cm^2 = 1.05 cm = h
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