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in the figure, both S1 and S2 are initially open. S2 is then closed and left closed until a constant current is established. The S2 is closed just as S1 is opened, taking the battery out of the circuit. Assume that R=515? and L= 305.0 mH

PART A

What is the initial current in the resistor just after S2 is closed and S1 is opened

PART B

What is the time constant of the circuit

PART C

What is the current in the resistor after a large number of time constants have elapsed

Added Tue, 04 Aug '15

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Solutions

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when S1 is closed, current i = V/R

i = 250/515

i = 0.485 Amps

-----------------------------------------

time constant T = L/R

T = 0.305/515

T = 0.592 msecs

----------------------------------------

after many long time constants I = 0.367 Io

I = 0.367 *0.458

I = 0.168 Amps

Added Tue, 04 Aug '15

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