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The magnetic field of the earth at a certain location is directed vertically downward and has a magnitude of 50.0 ï¿½T. A proton is moving horizontally toward the west in this field with a speed of 6.10 x 106 m/s. What are the direction and magnitude of the magnetic force the field exerts on the proton?

? N

Direction--- toward the north toward the east toward the west toward the south
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Use the right-hand rule to find the direction. Point the fingers of your right hand in the direction of motion (west), then curl them 90 degrees until they point in the direction of the magnetic field (down). What direction is your outstretched thumb pointing?

As for the magnitude, I trust you can multiply the speed of the proton by the magnetic field intensity to find the size of the resultant force.

magnetic force F = qvB sin theta

F = 1.6e-19 * 6.1e6*50e-6

F = 4.88*10^-17 N toward the east
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