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A student doing an experiment pours 0.160kg of heated copper shot into a 0.355-kg aluminum calorimeter cup containing 0.240kg of water. The cup and water are both initially at 20 C. The mixture (and the cup) comes to thermal equilibrium at 22 C.

What was the initial temperature of the shot?
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Heat Absorbed by a cool object will equal the heat released by the warm object....

heat cup + heat water = heat of shot
mc(tf-ti) + mc(tf-ti) = mc(ti-tf)
355 g(0.897 J/gC)(22-20 C) + 240 g(4.186 J/gC)(22 - 20 C)
= 160 g (0.127 J/gC)(ti - 22)

ti = 152.22C
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