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a car moving at 140 mi/hr passes a stationary police car whose siren has a frequency of 500hz. what is the frequency change heard by an observer in the moving car as he passes the police car? the velocity of sound in air is 343m/s. (1mi=1.609km) answer in Hz
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v = 140*1.6 = 224 km/hr = 62.22 m/sec

initial frequency when car was approaching:

f1 = f*(c/ (c - 62.22)

f1 = 610.79

final frequency when source is moving away

f2 = f*(c/(c+62.22)

f2 = 423.22

change = 610.79 - 432.22 = 187.56 Hz
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