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A block sliding to the right along a horizontal frictional surface has an initial velocity of 13.8m/s and stops in 135m due to friction with the surface. 1. Find the acceleration of the block. 2. Find the coefficient of kinetic friction between the block and the surface.
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Added Mon, 03 Aug '15
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v^2 = u^2 -2as       v=0   u=13.8   s=135

a = u^2/2s    = .70533 m/s^2

a = ug= .70533

u= .70533/g = .072
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Added Mon, 03 Aug '15
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