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A 4.51-kg object is thrown vertically upward from the surface of Venus, where the acceleration due to gravity is g1 = 8.87 m/s2. The initial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown with a speed of v2 = 1.63v1 from the surface of Saturn\'s moon Iapetus? The acceleration due to gravity on Iapetus is g2 = 0.223 m/s2. Give your answer as a multiple of y1.

IE: y2 = ? * y1
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We know that h=v^2/2g

y1=v1^2/2g1
=v1^2/2*8.87

v1^2=17.74y1

y2=(1.63v1)^2/2*0.223
y2=5.957 v1^2

y2=105.6 y1
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