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1

The current ia in the circuit shown in Fig. is 2 mA.

Find (a) i0; (b) ig; and (c) the power delivered by the independent current source.

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Added Sat, 25 Feb '17
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a)

Voltage across resistor 1k: $$V_{1k} = 2*1-^{-3}mA*1*10^3 \Omega = 2V$$

Voltage across resistor 4k: $$V_{4k} = 2*1-^{-3}mA*4*10^3 \Omega = 8V$$

Voltage across resistor 3k: $$V_{3k} = 2*1-^{-3}mA*3*10^3 \Omega = 6V$$

Voltage across two parallel branches is the same, thus:

Voltage across resistor 2k: $$V_{2k} = V_{1k} + V_{4k} + V_{3k} = 16V$$

$$I = V/R$$, -> $$i_0 = 16V/(3*10^3\Omega) = 8mA$$

b)

$$ i_g = i_a + i_0 = 10mA$$

c)

$$P = I*V$$, $$P = 10mA * 16V = 0.16W$$

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Edited Sat, 15 Apr '17
Added Sat, 15 Apr '17
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