ToughSTEM
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0
Bored, a boy shoots his pellet gun at a piece of cheese that sits, keeping cool for dinner guests, on a massive block of ice. On one particular shot, his 1.2 g pellet gets stuck in the cheese, causing it to slide 25 cm before coming to a stop. If the muzzle velocity of the gun is 64 m/s and the cheese has a mass of 123 g, what is the coefficient of friction between the cheese and ice?
Edit
Community
1
Comment
Solutions
0
given :
muzzle velocity = 64 m/sec

so.. velocvity of bullet just before hitting the cheese = 64 m/sec

momentum of bullet just before hitting chese = mass of bullet * velocity = 1.2 * 64 = 76.8 g * m/sec

after sticking in cheese... let the velocity of the bullet + cheese be v ...

so.. momentum after collision = (123+1.2)*v

now.. conserving momentum :
124.2 * v = 76.8

so.. velocity of cheese + bullet = 76.8 / 124.2 = 0.61836 m/sec ..

so.. kinetic energy of cheese + bullet system = 0.5 * mass * v^2 = 0.5 * 0.1242*0.61836^2 = 0.023745 J

let the coefficient of friction be mu ....

now.. friction force = mu * mass *g = mu * 0.1242 * 9.81

work done by friciton = friceion force * distance = 0.1242 * 9.81 * 0.25 * mu

now...
work done by friction = kinetic energy of bullet + cheese

so... 0.1242 * 9.81 * 0.25 * mu = 0.023745

so. coefficeint = mu = 0.077954
Edit
Community
1
Comment
Close

Choose An Image
or
Get image from URL
GO
Close
Back
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!