ToughSTEM
Sign Up
Log In
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0
A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 40.0 min at 90.0 km/h, 19.0 min at 80.0 km/h, and 40.0 min at 50.0 km/h and spends 25.0 min eating lunch and buying gas. (a) Determine the average speed for the trip. km/h (b) Determine the distance between the initial and final cities along the route. km
Edit
Added Mon, 03 Aug '15
Community
1
Comment
Add a Comment
Solutions
0
(b) Distance = Velocityx Time

Total distance travelled = (90 km/h)(40/60 h) + (80 km/h)(19/60 h) + (50 km/h)(40/60 h)

= 356/3 km

Total distance travelled = 118.67 km

------------------------------------------------------------------------------------------------------------------------------------

(a) Average speed of trip = Total distance travelled / Total time taken

= (118.67 km)/(40/60 +19/60 +40/60 +25/60)

= 118.67/2.066

Average speed of trip = 57.42 km/h
Edit
Added Mon, 03 Aug '15
Community
1
Comment
Add a Comment
Add Your Solution!
Close

Click here to
Choose An Image
or
Get image from URL
GO
Close
Back
Add Image
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

Add Your Solution
Sign Up
to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!
Please check your email to finish creating your account!
Welcome to the Club!
Choose a new Display Name
Only letters, numbers, spaces, dashes, and underscores, are allowed. Can not be blank.
Great! You're all set, .
A question answer community on a mission
to share Solutions for all STEM major Problems.
Why
The Purpose
How
The Community
Give Feedback
Tell us suggestions, ideas, and any bugs you find. Help make ToughSTEM even better.