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Coherent microwaves of wavelength 5.00 cm enter a tall, narrow building otherwise essentially opaque to the microwaves. If the window is 45 cm wide, what is the distance from the central maximum to the first-order minimum along a wall 6.50 m from the window?
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Added Sun, 21 Jun '15
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Given that

Wavelength of the microwave ? = 0.05 m

Width of slit d = 0.45 m

Distance slit and screen L = 6.50 m

Relation between the wavelength and width of the slit is given by

d sin? = m?

The angle is ? = sin-1[?/d]

= sin-1[0.05 m/0.45 m]

= 6.370

The distance from the centralmaximum to the first-order minimum is

y = L tan?

= (6.50 m) tan 6.370

= 0.726 m

= 72.6 cm
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Added Sun, 21 Jun '15
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