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A light ray initially in water enters a transparent substance at an angle of incidence of 39.0Ã¯Â¿Â½, and the transmitted ray is refracted at an angle of 25.0Ã¯Â¿Â½. Calculate the speed of light in the transparent substance.

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incident angle, theta_i = 39 degrees

refracted angle, theta_r = 25 degrees

refracive index of water, n1 = 1.33

let n2 is the refracitve index of unknown material.

According snell's law

sin(theta_i)/sin(theta_r) = n2/n1

==> n2 = n1*sin(theta_i)/sin(theta_r)

= 1.33*sin(39)/sin(25)

= 1.98

velocity of light in unknown material, v = c/n2

= 3*10^8/1.98

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