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an ideal gas expands to 6 times its original volume, maintaining constant 450K temperature. if gas does 5.3 KJ of work on its surrounding, how heat does it absorbs? and how many moles of gas are there?
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Added Mon, 03 Aug '15
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Vi = V, Vf = 6V (initial and final volumes)

T= constant = 450 kJ

Wgas = 5300 J

Now since its an isothermal process;

delta Q = Workdone by gas = 5300J =5.3 KJ

Also,

p = nRT/V = constant/V =K/V

Now workdone by gas = integral (pdV)(from Vi to Vf)

= nRT ln(Vf/Vi)

5.3 *1000= n *8.314*450*ln(6)

=> n = 5300/(8.314*450*ln(6)) =0.79 moles
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