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A cyclist starts from rest and pedals such that the wheels of his bike have a constant angular acceleration. After 20.0 s, the wheels have made 116 rev.

a.) What is the angular acceleration of the wheels?

b.) What is the angular velocity of the wheels after 20.0 s?

c.) If the radius of the wheel is 34.0 cm, and the wheel rolls without slipping, how far has the cyclist traveled in 20.0 s?
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Added Mon, 03 Aug '15
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? is the angulaar displacement
? is the angular acceleration.
?is the angular velocity
N is the frequency.
1 revolution = 2? radian.
--------------------------------------...



? = 1/2 *? *t^2
2? *116 = 1/2 *? *20^2
?= 4*3.14*116/ (20*20) = 3.64 rad/s^2
---------------------------------
?2 = ?*t = 3.64*20 = 72.88 rad /s
======================
Angle traversed = 2? *116. Radian
s = r? = 0.34*2? *116 = 247.8.m
===============================

Angular acceleration of the wheels = 0.91 rad/s^2
Angular velocity of the wheels after 14.0 s= 18.2 rad /s
Distance traveled in 14.0 s by the cyclist = 247.8.m
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