ToughSTEM
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0
When a voltage of 16.0 V is applied across the two ends of a cylindrical wire of length l, radius r and resistivity p, an electric current of 1.0 A is measured. Then the same voltage is applied to a second wire with length of 6l, radius of 2r and resistivity of 7p. What is the electric current measured in this second wire?
Edit
Community
1
Comment
Solutions
0
16 = pL/(pi r^2) * 1 for the first

for the second :

R = (7p) (6L) / pi(4 r^2)

= (42/4) [pL/(pi r^2)]

= (42/4) (16) = 168 ohm

hence i = 16 / 168 = 0.0952 A
Edit
Community
1
Comment
Close

Choose An Image
or
Get image from URL
GO
Close
Back
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!