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A ball of mass 2.50kg and radius 0.159m is released from rest on a plane inclined at an angle theta=39.0 degrees with respect to the horizontal. How fast is the ball moving (in m/s) after it has rolled a distance d=1.35m? 
Assume that the ball rolls without slipping, and that its moment of inertia about its center of mass is 1.60x10^-2 kg*m2.
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Added Sun, 21 Jun '15
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energy conservation

mgdsin(39)=0.5(I+mr^2)*w^2

20.814 J=0.5*(0.016+2.5*0.159^2)*w^2

w=22.926 rad/sec

V=wr=3.645 m/sec (ans)
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Added Sun, 21 Jun '15
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