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026 (part 1 of 3) 10.0 points

We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 4.6 g. Find the number of atoms in a nickel coin. Each mole (6.02 x 10^23 atoms) has a mass of about 57.8 g. Answer in units of atoms

027 (part 2 of 3) 10.0 points

Find the number of electrons in the coin. Each nickel atom has 28 electrons/atom. Answer in units of electrons

028 (part 3 of 3) 10.0 points

Find the magnitude of the charge of all these electrons. Answer in units of C
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Added Thu, 30 Jul '15
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(a) we have mass of 6.02*10^23 of atoms of nickel is 58.1 g
so, the no.of atoms in a mass of 4.6g = 4.6/57.8 * 6.02*10^23
= 4.766 * 10^22 atoms
so,the no.of nickel atoms in a mass of 4.6g = 4.766 * 10^22 atoms

(b) total no.of electrons = 4.766 * 10^22 * 28 = 1.334 * 10^24 electrons

(c) magnitude of of each electron = 1.6 * 10^-19 C
so,the magnitude of the charge of all these electrons = (1.6 * 10^-19) * (1.334 *10^24)
= 2.13 * 10^5 C
so,the magnitude of the charge of all these electrons = 2.13 * 10^5 C
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Added Thu, 30 Jul '15
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