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A motor is designed to operate on 117 V and draws a current of

13.3 A when it first starts up. At its normal operating speed, the

motor draws a current of 1.92 A. Obtain (a) the resistance of the

armature coil, (b) the back emf developed at normal speed, and (c)

the current drawn by the motor at one-third normal speed.

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a)

R=V/I =117/13.3

R=8.8 ohms

b)

E=V-I*R =117-1.92*8.8

E=100.1 Volts

c)

at (1/3)rd of normal speed ,back emf is (1/3) of its maximum

value

E=(1/3)*100.1=33.37 Volts

Current drawn

I=V-Eback/R =117-33.37/8.8

I=9.5 A

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