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A current of 27.0 mA is maintained in a single circular loop of 1.30 m circumference. A magnetic field of 0.900 T is directed parallel to the plane of the loop.

(a) Calculate the magnetic moment of the loop.

(b) What is the magnitude of the torque exerted by the magnetic field on the loop?

Added Mon, 27 Jul '15

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current : I = 27.0 mA = 0.027 Ampere

circumference = 1.30 m = 2 Pi r

-> r = 1.30/2Pi = 0.207 m

surface area a circular loop : A = Pi r^2 = 0.13455 m^2

magnetic field : B = 0.900 T

the magnitude of the torque :

=> tq = N I B A sin Theta

for : N = 1 and Theta = 90 Degrees

then : tq = I B A

===> tq = 0.027 x 0.90 x 0.13455

===> tq = 3.269 x 10^-3 N m

Added Mon, 27 Jul '15

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