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As shown in the figure, a ray of light strikes a plane mirror with some incident angle. The mirror is now rotated by an angle of ? = 34.0(?) about an axis through the point where N1 contacts the mirror, without altering the incident ray. The new position is shown by the line M2.

(a) Determine the angle through which the reflected ray rotates if the incident angle is 40.0.


(b) Determine the angle through which the reflected ray rotates if the incident angle is 50.0.

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Added Sun, 26 Jul '15
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suppose with respect to n1 the light may be incident at angle'\theta' then reflected ray makes angle ' \theta ' with n1 .

when the mirror is rotated through angle alpha  then the new normal n2 makes angle '\alpha' with n1.

so,the angle between n2 and the first reflected ray will be  \alpha - \theta

so,the light ray makes angle theta +alpha with respect to new normal n2.so the new reflected ray makes angle theta+alpha with the normal n2.

the newly reflected ray makes angle theta+alpha  with n2 and first reflected ray makes alpha - theta with n2.

so,the reflected ray rotates by =  theta+alpha  -(alpha - theta ) =2\theta = 68 degrees
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Added Sun, 26 Jul '15
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