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Consider the system shown in the figure below. Block A

weighs 44.8 N and block B weighs 29.0 N. Once block

B is set into downward motion, it descends at a constant

speed.

(a) Calculate the coefficient of kinetic friction between block

A and the tabletop.

(b) A cat, also of weight 44.8 N, falls asleep on top of block

A. If block B is now set into downward motion,

what is its acceleration?

magnitude

=? m/s2

Consider the system shown in the figure below. Block A weighs 44.8 N and block B weighs 29.0 N. Once block B is set into downward motion, it descends at a constant speed. (a) Calculate the coefficient of kinetic friction between block A and the tabletop. (b) A cat, also of weight 44.8 N, falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration?

Edit
Added Thu, 25 Aug '16
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Solutions
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a)

For block force in horizontal :

T = ukWa becoz block B has

constant velocity implies acceleration is zero implies all forces

balances each other

For block B

T = Wb

ukWa = Wb

uk = .647

b)

acceleration = 0

becoz now Kinetic force = uWa' will be

greater than before as Wa' = 44.8 44.8 =

89.6

Edit
Added Thu, 25 Aug '16
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