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A batted baseball leaves the bat at an angle of 34.0 degrees

above the horizontal and is caught by an outfielder 365ft from home

plate at the same height from which it left the bat.

What was the initial speed of the ball?

How high does the ball rise above the point where it struck the

bat?

Edit
Added Thu, 25 Aug '16
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we can use the range equation:

range = v0^2 sin(2 theta)/g

365ft = v0^2 sin(2 x 34)/32.3ft/s/s

v0 = 112.76ft/s

the initial vertical velocity is v0 sin(theta) = 112.76 sin 34 =

63.05ft/s

the max height = (initial vertical velocity)^2/2g =

(63.05ft/s)^2/2x32.2ft/s = 61.73ft

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Added Thu, 25 Aug '16
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