initial speed=v=22 m/s
mass=m=7.3 gm=7.3*10^(-3) kg
let the angle be theta.
then vertical component of initial speed=22*sin(theta)
in horizontal direction,acceleration is 0.
so velocity will remain unchanged.
in vertical direction,acceleration is 9.8 m/s^2,downwards
so velocity at time t is given by :
now time taken to reach ground=2*time taken to reach the maximum height
at maximum height,vertical component is 0.