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A thin film of acetone (n = 1.25) coats a thick glass plate (n = 1.50). White light is incident normal to the film. In the reflections, fully destructive interference occurs at 600 nm and fully constructive interference at 700 nm. Calculate the thickness of the acetone film.
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as we know that

2L = (m + 0.5)lambda/n2

When

n2 = 1.25

lambda = 700 nm

L = 0 ,280 nm , 560 nm , 840 nm , 1120 nm

Similarly

when n2 = 1.5
lambda = 600 nm

L = 120 , 360 , 600, 840 nm

Hence

L = 1120 -1080 = 840 nm
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