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A student of weight 673 N rides a steadily rotating Ferris wheel

(the student sits upright). At the highest point, the magnitude of

the normal force FN on the student from

the seat is 558N.

(a) Does the student feel "light" or "heavy" there?

(b)What is the magnitude of FN at

the lowest point?

(c) If the wheel's speed is doubled, what is the magnitude of

FN at the highest point?

(d) What is the magnitude of FN at the

lowest point under the same conditions as in (c)?

Edit
Added Fri, 15 Jul '16
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a) Lighter.

Mass of student = (673/9.8) = 68.67kg.

Centripetal acceleration component = ((9.8 x (558/673)) - 9.8 =

-1.674 m/sec^2.

So at the bottom, total acceleration will be (9.8 1.674) = 11.474

m/sec^2.

b) Force at bottom = (ma) = (11.474 x 68.67) = 787.91 N.

c) Centripetal force is quadrupled when speed is doubled, = (1.674

x 4) = 6.696 m/sec^2.

(9.8 - 6.696) x 68.67 = 213.15 N.

d) (9.8 6.696) x 68.67 = 1,132.78N.

Edit
Added Fri, 15 Jul '16
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