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Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon's tongue accelerates at a remarkable 280m/s2 for 20 ms, then travels at constant speed for another 30 ms .
During this total time of 50 ms , 1/20 of a second, how far does the tongue reach?
Express your answer to two significant figures and include the appropriate units.
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Added Fri, 24 Jul '15
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distance (during acceleration) = 0.5 a t^2

= 0.5 * 280 * 0.02^2

= 0.056

v = at = 280*0.02 = 5.6

distance (durig const speed) = v t

= 5.6 *0.03 = 0.168

total diatance = 0.056 + 0.168

= 0.224m

= 22.4 cm

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Added Fri, 24 Jul '15
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