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Two spheres are launched horizontally from a 1.2m -high table. Sphere A is launched with an initial speed of 5.0m/s . Sphere B is launched with an initial speed of 3.0m/s .
1) What is the time for the sphere A to hit the floor?
2)What is the time for the sphere B to hit the floor?
3)What is the distance that sphere A travels from the edge of the table?
4)What is the distance that sphere B travels from the edge of the table?
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Since the balls are launched horizontally, there is no vertical motion.
So

d = 1/2 at^2
1.2 = 1/2(9.8)t^2
t = 0.495s

Gravity will affect both balls equally. So they both hit the ground in 0.495seconds.

b)d = vt <---Sphere A
d = (4.5)(0.495)
d = 2.23m

Sphere B
d = vt
d = 1(0.495)
d = 0.495m
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