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A person with compromised pinch strength in their fingers can

only exert a normal force of 6.0 N to either side of a pinch-held

object, such as the book shown in (Figure 1) .

What is the mass of the heaviest book this person can

hold onto vertically before it slips out of his or her fingers? The

coefficient of static friction of the surface between the fingers

and the book cover is 0.60.

include the appropriate units.

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Heaviest book has weight

= (6 6) * 0.6 N

= 7.2 N

If m = mass of the heaviest book in kg

m

=7.2/9.81 kg

= 0.733 kg.

or

You have two normal forces (N) of 6N thus F = 2�N = 2*.6*6N =

7.2N

Therefore the book cannot weigh more than 7.2 N.

m=W/g = 7.2N/(9.8m/s^2) = .735kg

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