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The velocity of an object moving along the x axis is given by vx = (2.0 t ? t2) m/s. Initially, at t = 0, the object was at the origin. What is the object's position at t= 1.0s, 2.0s and 3.0 s?

Added Wed, 22 Jul '15

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vx = dx/dt

dx = vx*dt

dx = (2*t - t^2)*dt

integrate both sides

x = 2*t^2/2 - t^3/3

= t^2 - t^3/3

at t = 1 s

x1 = 1^2 - 1/3 = 2/3 = 0.6667 m

at t = 2s

x2 = 2^2 - 2^3/3 = 1.333 m

at t = 3s

x3 = 3^2 - 3^3/3 = 0

Added Wed, 22 Jul '15

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