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When monochromatic light shines perpendicularly on a soap film (n = 1.33) with air on each side, the second smallest nonzero film thickness for which destructive interference of reflected light is observed is 430 nm. What is the vacuum wavelength of the light in nm?
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The condition for the destructive interferenceis
2nt = m(lambda)
Here m =2
So the wavelength of light in vacuum is
(lambda)= (2nt)/2
(lambda)=1.33* 430
?=571.9nm
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