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12) An advertisement claims that a certain 1200-kg car can

accelerate from rest to a speed of 25 m/s in 8.0 s. What average

power must the motor supply in order to cause this acceleration?

Ignore losses due to friction.

Edit
Added Sun, 03 Jul '16
Treebeard
31978
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Solutions
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Power is Energy/Time. The amount of energy to go from 0 to 25

m/s is 1/2*m*v**2. Then divide this by time to get average

power.

P = 1/2*m*v**2/t = 1/2*1200*25**2/8 = 46.9kW

Edit
Added Sun, 03 Jul '16
Treebeard
31978
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