12) An advertisement claims that a certain 1200-kg car can
accelerate from rest to a speed of 25 m/s in 8.0 s. What average
power must the motor supply in order to cause this acceleration?
Ignore losses due to friction.
Power is Energy/Time. The amount of energy to go from 0 to 25
m/s is 1/2*m*v**2. Then divide this by time to get average
P = 1/2*m*v**2/t = 1/2*1200*25**2/8 = 46.9kW