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A parallel-plate vacuum capacitor has 6.88J of energy stored in

it. The separation between the plates is 3.70mm . If the separation

is decreased to 1.25mm ,

Part A

what is the energy now stored if the capacitor was disconnected

from the potential source before the separation of the plates was

changed?

U = J

Part B

What is the energy now stored if the capacitor remained

connected to the potential source while the separation of the

plates was changed?

U = J

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Solutions
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before separation energy U = 6.88 J

----------------------------

apply enegry U = 0.5 QV

also as V = Ed

U is directicly proportional to d

so U2/U1 = d2/d1

U2 = 6.88*1.25 mm/3.7

U2 = 2.32 J

--------------------------------------------

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