ToughSTEM
Sign Up
Log In
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0
A railroad car of mass 2.40 x 104 kg is moving with a speed of 3.82 m/s. It collides and couples with three other coupled railroad cars, each of the same mass as the single car and moving in the same direction with an initial speed of 1.91 m/s.
(a) What is the speed of the four cars after the collision?
(...........) m/s

(b) How much mechanical energy is lost in the collision?
(..........) J
Edit
Added Tue, 21 Jul '15
Community
1
Comment
Add a Comment
Solutions
0

Here Momentum remains Conserved

Therefore

mv + 3mu = (m+m+m+m)*V

v + 3u = 4V

3.82 + 3*1.91 = 4*V

V = 2.3875 m/sec

================================

Mechanical Energy Lost = 0.5*m*v^2 + 0.5*3m*u^2 - 0.5*4m*V^2

= (0.5*2.40*10^4)*(3.82^2 + 3*(1.91^2) - 4*(2.3875^2))

= 32832.9 J
Edit
Added Tue, 21 Jul '15
Community
1
Comment
Add a Comment
Add Your Solution!
Close

Click here to
Choose An Image
or
Get image from URL
GO
Close
Back
Add Image
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

Add Your Solution
Sign Up
to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!
Please check your email to finish creating your account!
Welcome to the Club!
Choose a new Display Name
Only letters, numbers, spaces, dashes, and underscores, are allowed. Can not be blank.
Great! You're all set, .
A question answer community on a mission
to share Solutions for all STEM major Problems.
Why
The Purpose
How
The Community
Give Feedback
Tell us suggestions, ideas, and any bugs you find. Help make ToughSTEM even better.