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A railroad car of mass 2.40 x 104 kg is moving with a speed of 3.82 m/s. It collides and couples with three other coupled railroad cars, each of the same mass as the single car and moving in the same direction with an initial speed of 1.91 m/s.
(a) What is the speed of the four cars after the collision?
(...........) m/s

(b) How much mechanical energy is lost in the collision?
(..........) J
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Here Momentum remains Conserved

Therefore

mv + 3mu = (m+m+m+m)*V

v + 3u = 4V

3.82 + 3*1.91 = 4*V

V = 2.3875 m/sec

================================

Mechanical Energy Lost = 0.5*m*v^2 + 0.5*3m*u^2 - 0.5*4m*V^2

= (0.5*2.40*10^4)*(3.82^2 + 3*(1.91^2) - 4*(2.3875^2))

= 32832.9 J
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