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A feather is dropped on the moon from a height of 3 meters. The acceleration of gravity on the moon is 1.67 m/s^2. Determine the time for the feather to fall to the surface of the moon.
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First - Remember our Basic Kinematic Equation

When velocity and acceleration are constant :
x = x_0 + v * t + 1/2 * a * t^2

In the case of the feather - we are trying to figure out the variable (t) over a total distance of 3 meters.

x - x_0 = 3, thus

3 = v*t + 1/2 * a *t^2

Because the feather is dropped - not thrown - the initial velocity is 0.

Thus the equation is,

3 = 0*t + 1/2 * a * t^2
= 1/2 * a * t^2

Solve for t.

3 = 1/2 * a * t^2
>> 6 = a * t^2
>> 6 / a = t^2
>> sqrt ( 6/a ) = t
>> sqrt( 6 / 1.67 ) = t
>> 1.895 = t

t = 1.895 seconds
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