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A 723-N person stands on a uniform board of weight 282 N and length 6.1 m. The board is supported 1.00 meter in from the left end and 0.500 meters in from the right end. The support force 1.00 meters in from the left end is 683 N.
a) What is the support force 0.500 meters in from the right end?
b) How far from the left end of the board is the person standing?
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a.)Since board is in equlibrium
723 + 282 = 683 + R
R = 322 N

So the support force 0.500 meters in from the right end is 322 N

b.)Take moments from left end and let distance be D
282 x 3.05 + D x 723 = 1 x 683 + 5.6 x 322
D = 2.25 m

So the person is standing 2.25 m from the left end.
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