A projectile is fired at v0 = 433.0 m/s at an angle of ? = 69.0o with respect to the horizontal. Assume that air friction will shorten the range by 35.1%. How far will the projectile travel in the horizontal direction, R?
original range, R = u^2*sin(2*theta)/g = 433^2 *sin(2*69)/9.8 = 12801.49 m
shortened range = (1 - 0.351)* 12801.49 = 8308.167 m