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A wave travels along a string of linear mass density ? = 0.03kg/m described by the wave function

y(x,t) = 0.27 cos(4.5x?30t +?/12)

Calculate the net force on the section of the string that is 0.005m long, and whose center is 0.025m from the left-end of the string, after the wave has been traveling on the string for 0.07s

Added Mon, 20 Jul '15

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y(x,t) = 0.27cos(4.5x-30t+?/12)

dy/dt(Partial Derivative) = 0.27*(-30)*(-sin(4.5x-30t+?/12))

d2y/dt2 (Partial) = -0.27*900*cos(4.5x-30t+?/12)

Putting x=0.025m, t=0.07s

acceleration = d2y/dt2 = -37.491

Mass of element = ?*l = 0.03*0.005 = 0.00015

Therefore, Force = Mass x Acceleration = -5.624*10-3 N

Added Mon, 20 Jul '15

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