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A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 49.0m/s2 . The acceleration period lasts for time 5.00s until the fuel is exhausted. After that, the rocket is in free fall.. Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s2 .

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height reached during acceleration = 05*a*t2 = 0.5*49*52 = 612.5 m

velocity reached = at= 49*5 = 245m

For max. height , final velocity = 0

distance travelled = ut - 0.5 gt2

time taken for above distance = 245/9.8 = 25 sec.

distance travelled = ut - 0.5 gt2 = 3062.5 m

Total height = 3062.5 + 612.5 = 3675m

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