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2nF and a 5nF capacitors are connected in series to a 12V battery. Find voltage in a 5nF capacitor.
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Added Mon, 20 Jul '15
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Charge on a capacitor is Q=CV

If you have two capacitors(C1 and C2) the charge across them is Q1 =C1*V1 and Q2=C2*V2
Two capacitors in series must hold the same charge so Q1=Q2.

C1*V1=C2*V2

V1=C2*V2/C1

By Kirchhoff's voltage law: V1+V2=12, plug in V1 from the previous step:
C2*V2/C1 + V2 = 12

5/2*V2+V2=12

7/2V2=12

V2=24/7 V
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