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A charge of -7.7 ?C is traveling at a speed of 7.4 x 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 50?. A force of magnitude 4.0 x 10-3 N acts on the charge. What is the magnitude of the magnetic field?
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Added Mon, 20 Jul '15
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F = QvB sin(theta)

Q - charge = 7.7 *10^-6

v - velocity = 7.4 multiply.gif 106

F- Force = 4.0 multiply.gif 10-3 N

B- Mgnetic Filed = ??

Theta = 50

So B = F/vQsin(50)

= 9.163 x 10-5 Tesla ........Ans

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Added Mon, 20 Jul '15
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