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In a period of 0.9 s, 5.0 1023 nitrogen molecules strike a wall of area 7.4 cm2. If the molecules move at 290 m/s and strike the wall head on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one N2 molecule is 4.68 10-26 kg.)
_________Pa
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Added Mon, 20 Jul '15
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For perfectly elastic collision, velocity of returning=-velocity of approach.

Change in velocity= 290-(-290)=580 m/s

Change in momentum of 1 molecule=mass*change in velocity=4.68*10-26*580=2.714*10-23 kg.m/s

Change in momentum of 5.0*10-23 molecule=2.714*10-23*5*1023=13.572 kg.m/s

Force applied from wall=change in momentum/time=13.572/0.9=15.08 N

Area= 7.4 cm2=7.4*10-4 m2

Pressure =Force /Area=15.08/7.4*10-4=20378.4 Pa
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