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A particle P is sliding down a frictionless hemisphere bowl. it passes the point A at t=0. At this instant of time, the horizontal component of its velocity is v. A bead Q of the same mass as P is ejected from A at t=0 along horizontal string AB with the speed v. Friction between bead and the string may be neglected. Let t(p) and t(q) be the respective times taken by P and Q tp reach the point B then

A. t(p)=t(q)

B. t(p)>t(q)

C. t(p)

Edit
Edited Sat, 09 Apr '16
Is there a diagram associated with this problem? UladKasach Fri, 08 Apr '16
Also, is 'horizontal spring' supposed to be 'horizontal string'? UladKasach Fri, 08 Apr '16
Yes. sorry I've edited MrBenzedrine Sat, 09 Apr '16
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P travels along the path of a bowl, a parabolic path.

Q travels along the path of the string, a straight path.

Because they have the same mass and same speed at point A, the distance between AB is shorter if you travel along a straight line than if you travel a parabolic path.

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