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A car traveling at 25m/s runs out of gas while traveling up a 9.0 degrees slope.

How far will it coast before starting to roll back down?

Express your answer using two significant figures.

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Added Wed, 06 Apr '16
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sin(9 degrees) = acceleration on hill due to gravity / gravity

sin(9 degrees) = accel / -9.81

accel = -1.53

final stopping velocity of 0 = V + at

0 = 25 m/s - 1.53t

t = 16.34

distance = Vt + 1/2at^2

distance = 25*16.34 - (1/2)(1.53)(16.34^2) = 204.25 m = 20*10^1 m

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Added Wed, 06 Apr '16
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