A car traveling at 25m/s runs out of gas while traveling up a 9.0 degrees slope.
How far will it coast before starting to roll back down?
Express your answer using two significant figures.
sin(9 degrees) = acceleration on hill due to gravity / gravity
sin(9 degrees) = accel / -9.81
accel = -1.53
final stopping velocity of 0 = V + at
0 = 25 m/s - 1.53t
t = 16.34
distance = Vt + 1/2at^2
distance = 25*16.34 - (1/2)(1.53)(16.34^2) = 204.25 m = 20*10^1 m
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