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A spring with a spring constant of 110N/m is stretched by 12 cm. How much force is applied to the spring to stretch it? 
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Added Mon, 20 Jul '15
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Elastic Strain Energy = (1/2)kx^2 where k is the spring constant and x is the extension

to work out the extension do 0.12m.*110N/m= 13.2 N

now we have our variables put them into the formula
(1/2) * 110Nm^-1 * (0.12)^2m^2 = 0.792J while it is a form of energy so the units are obviously Joules we can work it out that they are Joules our units in the equation are Nm^-1 * m^2 which simplifies to Nm which using the formula Work = Force * Distance and given Work has unit Joules then Newtons*Metres = Joules
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