An arrow is launched from a height of 1.21 m above the ground with an initial speed of 48.3 m/s and an initial angle of 35o above the horizontal. Assume air resistance is negligible.
a) At what time after the release of the arrow will the arrow be flying exactly horizontally? b) What will be the maximum height the arrow will reach during its trajectory?
a)time=v*sin(x)/g=48.3*sin(35 degree)/9.8=2.827 seconds
b)maximum height=1.21+(v*sin(x))^2/2g=(48.3*sin(35 degree))^2/2/9.8=40.368m