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I fire a bullet at a ballistic pendulum. The large block of wood has a mass M2 = 3.000 kg, and the bullet has a mass of m1 = 30.0g. The bullet completely penetrates the wood and emerges with a speed of vf = 80.0 m/s. The wood, as part of a pendulum, swings up to a maximum height of h = 7.00 cm.

(a) Determine the speed of the block of wood after the bullet has passed through it.

(b) What is the speed of the bullet just before it hits the block?
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Added Mon, 20 Jul '15
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Let u1 be the initial vel. of bullet and u2 be the speed of the block after the bullet has just passed through it.

a) Conservation of Total Energy of the combined system of Block and Bullet:-

Just after the bullet has passed through the block u2 and the finally wood block achieves a max height of 7cm.At max.ht final vel of block is 0.

u2=1.1719m/s

b) Conservation of momentum:-

Total Momentum before collision=m1*u1

Total momentum after collision=m1*vf+m2*u2

(30*10-3kg)*u1=(30*10-3kg)*80+(3kg)*u2

0.01u1=0.8+u2

u1=197.91m/s
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Added Mon, 20 Jul '15
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