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A 720 gram block is released from a height h above an ideal spring of spring constant 400 N/m. The block sticks to the spring, and comes momentarily to rest after compressing the spring by an amount of 18.3 cm.
(a) What is the value of the initial height h?  
(b) What is the height of the block when it again comes to rest momentarily--the block remains connected to the spring? Measure from the equilibrium position of the spring.
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Added Mon, 20 Jul '15
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(a) Loss in potential energy of the block = gain in potential energy of spring

mg(H+x)=0.5*K*x^2

0.72*9.81(h+0.183)=0.5*400*0.183^2

h=76.52 cm

(b) Total initial energy of the system = total final energy of the system

from equilibrium

0.5*K*0.183^2-mg*0.183=0.5*K*y^2 +mgy

we get y=14.77 cm
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Added Mon, 20 Jul '15
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