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A farsighted person can read printing as close as 25.0 cm when she wears contacts that have a focal length of 44.6 cm. One day, however, she forgets her contacts and uses a magnifying glass, as in the drawing. It has a maximum angular magnification of 6.01 for a young person with a normal near point of 25.0 cm. What is the maximum angular magnification that the magnifying glass can provide for her?
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First we need the near point of the person...

1/f = 1/p + 1/q
1/44.6 = 1/25 + 1/q
q = 56.9

Thus the near point is 56.9

For the normal person
m = 1+25/f
6.01 = 1 + 25/f
f = 4.99 cm

So the the person with the different near point...
m = 1 + 56.9/4.99
m = 12.4
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