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thin rod of length L with total charge Q. Find an expression for the electric field strength at point P on the axis of the rod at distance r from the center. Verify that your expression has the expected behavior if r L. Evaluate E at r = 3.0 cm if L = 5.0 cm and Q - 3.0 nC.

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Taking an element of length dx at distance x from the left end of the rod.

Charge on element=(Q/L)dx

Distance of element from P=(r+L/2-x)

Field at P due to the element=k(Q/L)dx/(r+L/2-x)^2

Integrating from x=0 to L to get the field,

E=4kQ/(4r^2-L^2)

b)If r>>L, L term in denominator is neglected, we get,

E=kQ/r^2 which is correct for a point charge.

c)E=4*9*10^9*3*10^-9/(4*0.03^2-0.05^2)=98182N/C

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